Why does silver chloride form a white precipitate in a chloride-ion test?

In a chloride-ion test, the formation of a white precipitate occurs because of the reaction between silver nitrate (AgNO₃) and chloride ions in a solution, which produces silver chloride (AgCl).1

This reaction is a standard analytical method used to identify the presence of chloride ions. When silver nitrate is added to a sample—typically in the presence of dilute nitric acid—the silver ions ($A{g}^{+}$) react with the chloride ions ($C{l}^{-}$) to form solid silver chloride. Because silver chloride is insoluble in water, it separates from the solution as a white precipitate. This precipitate is notable for being soluble in the presence of ammonia, which serves as a further confirmation during chemical analysis.1