Why do ultraviolet photons usually have more energy than visible-light photons?

Ultraviolet photons possess more energy than visible-light photons because the energy of a photon is directly proportional to its frequency.12

According to the relationship established in quantum mechanics, the energy (E) of a photon is calculated using the equation:
$$E=h\nu$$
In this formula, h represents Planck’s constant, and ν (nu) represents the frequency of the radiation.13

Because ultraviolet radiation occupies a position on the electromagnetic spectrum with higher frequencies and shorter wavelengths than visible light, each individual ultraviolet photon carries a greater amount of energy. While visible light photons typically range from about 1.8 eV to 3.1 eV, ultraviolet photons generally possess higher energies, often ranging from 4 to 10 eV, which allows them to initiate photochemical reactions that visible light cannot.2456